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Mathematics 20 Online
OpenStudy (anonymous):

\[\huge Calculas\quad Question\quad Of\quad the\quad DAY\]: If f is continuous on [m,n] and differentiable for ( m , n ), which of the following could be false? A) f ' (c) = ( f(n) - f(m) ) / ( m - n ) ) for some c is an element of (m ,n) B) f ' ( c ) = 0 for some c is an element of [ m , n ] C) f has a maximum on [ m , n ] D) f has a maximum on [ m , n ] E) All of the above are always true

OpenStudy (anonymous):

@saifoo.khan @lgbasallote @mathslover @moongazer can any one solve it

OpenStudy (ash2326):

I think it's option A

OpenStudy (anonymous):

A doesn't have limits in the definition, so it's not rigorous.

OpenStudy (foolaroundmath):

Its A and B (If (a) was (f(n)-f(m))/(n-m) then it would be true since its the statement of the Mean Value Theorem). B is clearly false, Take f(x) = x as an example. It is continuous and differentiable but nowhere is its derivative 0

OpenStudy (anonymous):

First, C&D are the same, they're true Second, A is false becos the right sentence should be: \[\huge f ' (c) = ( f(m) - f(n) ) / ( m - n ) ) \]for some c is an element of (m ,n) yea i missed it B is false too, the prerequisite for B to be true is that \[\huge f(m) = f(n)\]

OpenStudy (anonymous):

answer

OpenStudy (anonymous):

Alright, I'll give a better response. No expression of the derivative's formal statement as a limit can be configured into a way such that all the slopes can be simplified into the average slope.

OpenStudy (anonymous):

aM i RiGhT

OpenStudy (anonymous):

Yes, I didn't notice B either. It's wrong as well.

OpenStudy (anonymous):

a medal

OpenStudy (anonymous):

How do I shot medal?

OpenStudy (anonymous):

a medal for me

OpenStudy (anonymous):

@mathslover

OpenStudy (anonymous):

Can't tell if this is pandering.

OpenStudy (anonymous):

okay any one left

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