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Mathematics 8 Online
OpenStudy (anonymous):

Answer pls !

OpenStudy (anonymous):

|dw:1341746767680:dw|

OpenStudy (anonymous):

what's your question ?

OpenStudy (anonymous):

find the adjacent and hypotenuse :)

OpenStudy (anonymous):

is that a right-angled triangle ?

OpenStudy (anonymous):

it is not stated. I dont think so :)

OpenStudy (anonymous):

have u learned the cos rule ?

OpenStudy (anonymous):

just by using SOHCAHTOA :)

OpenStudy (anonymous):

Cos rule? Nah.

OpenStudy (anonymous):

if its not a right-angled triangle, you can't use SOHCAHTOA, but you can use the cosine rule

OpenStudy (anonymous):

how? :)

OpenStudy (anonymous):

aa wait you can't use cosine rule, because you only have one side.. are you sure this is not a right-angle triangle ?

OpenStudy (anonymous):

I dont know haha :)

OpenStudy (anonymous):

Out teacher taught us teh SOHCAHTOA method and also the pythagorean theorem then she gave us that assignment. I dont actually get it XD

OpenStudy (anonymous):

i'll eat first :)

OpenStudy (anonymous):

because you haven't learnt cosine rule, maybe the diagram should be like this |dw:1341747215415:dw| here, to find the adjacent, use \[\tan \theta = opposite / adjacent \] \[adjacent = 5/\tan47 = 4.663 units\] to find the hypotenuse, use \[\sin \theta = opposite / hypotenuse\]\[hypotenuse = 5/\sin47 = 6.837 units\]

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