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OpenStudy (anonymous):
|dw:1341746767680:dw|
OpenStudy (anonymous):
what's your question ?
OpenStudy (anonymous):
find the adjacent and hypotenuse :)
OpenStudy (anonymous):
is that a right-angled triangle ?
OpenStudy (anonymous):
it is not stated. I dont think so :)
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OpenStudy (anonymous):
have u learned the cos rule ?
OpenStudy (anonymous):
just by using SOHCAHTOA :)
OpenStudy (anonymous):
Cos rule? Nah.
OpenStudy (anonymous):
if its not a right-angled triangle, you can't use SOHCAHTOA, but you can use the cosine rule
OpenStudy (anonymous):
how? :)
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OpenStudy (anonymous):
aa wait you can't use cosine rule, because you only have one side..
are you sure this is not a right-angle triangle ?
OpenStudy (anonymous):
I dont know haha :)
OpenStudy (anonymous):
Out teacher taught us teh SOHCAHTOA method and also the pythagorean theorem then she gave us that assignment. I dont actually get it XD
OpenStudy (anonymous):
i'll eat first :)
OpenStudy (anonymous):
because you haven't learnt cosine rule, maybe the diagram should be like this |dw:1341747215415:dw|
here, to find the adjacent, use
\[\tan \theta = opposite / adjacent \]
\[adjacent = 5/\tan47 = 4.663 units\]
to find the hypotenuse, use
\[\sin \theta = opposite / hypotenuse\]\[hypotenuse = 5/\sin47 = 6.837 units\]