Answer pls !
|dw:1341746767680:dw|
what's your question ?
find the adjacent and hypotenuse :)
is that a right-angled triangle ?
it is not stated. I dont think so :)
have u learned the cos rule ?
just by using SOHCAHTOA :)
Cos rule? Nah.
if its not a right-angled triangle, you can't use SOHCAHTOA, but you can use the cosine rule
how? :)
aa wait you can't use cosine rule, because you only have one side.. are you sure this is not a right-angle triangle ?
I dont know haha :)
Out teacher taught us teh SOHCAHTOA method and also the pythagorean theorem then she gave us that assignment. I dont actually get it XD
i'll eat first :)
because you haven't learnt cosine rule, maybe the diagram should be like this |dw:1341747215415:dw| here, to find the adjacent, use \[\tan \theta = opposite / adjacent \] \[adjacent = 5/\tan47 = 4.663 units\] to find the hypotenuse, use \[\sin \theta = opposite / hypotenuse\]\[hypotenuse = 5/\sin47 = 6.837 units\]
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