Question

factor
3x^2+10x-8

Answer 1

You can factor by splitting the middle term or use the Quadratic formula to factor this

Answer 2

Have you tried any of the two?

Answer 3

When you split the middle term of a quadratic equation of the form\(\large ax^2+bx+c\)

the first thing you have to do is to find 2 numbers whose product is \(\large a \times c ~or~~ ac\)
and their sum is \(\large 'b'\)

Coming back to your question:
\(\large 3x^2 + 10x -8\)

here \(\large a=3,~~b=10,~~c=-8\)

Now you need two numbers whose product is \(\large 3 \times -8 =-24\) and sum is \(\large10\)

Answer 4

wait

Answer 5

(3x + 2)( x - 4)

check 3x*x
3x*-4
2*x
2*-4

Answer 6

@arabella12345 Can you try to find those numbers?

Answer 7

x=-4,2/3

Answer 8

3x^2+10x-8
=>3x^2+12x-2x-8
=>3x(x+4)-2(x+4)
=>(3x-2)(x+4).