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Chemistry 56 Online
OpenStudy (anonymous):

'Manufacture' the following compounds starting from hydrocarbons. a) 2-pentanone b) propandioc acid c) s-butyl athanoate d) N,N-diethyl-2-amonoheptane e) isopropyl butanamide

OpenStudy (anonymous):

I can only help with a so, React pentene with either acidified water, potassium permanganate or potassium dichromate to produce the secondary alcohol pentan-2-ol CH2=CH-CH2-CH2-CH3 + (acidified reagent) --> CH3-CH(OH)-CH2-CH2-CH3 React this newly formed solution again with one of the acidified reagents and take Markovnikovs major product CH3-CH(OH)-CH2-CH2-CH3 + (acidified reagent) --> CH3-C(O)-CH2-CH2-CH3 The attached picture is the only way I know of synthesizing propandioc acid although it doesn't begin with a simple hydrocarbon.

OpenStudy (anonymous):

b) propandioc acid

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