The figure shows a triangular park ABC. The area DEFC is cordoned off by putting barricades on the sides DE and EF.

What is the total length of the barricades DE and EF?

Question

The figure shows a triangular park ABC. The area DEFC is cordoned off by putting barricades on the sides DE and  EF.
 

 
What is the total length of the barricades DE and EF?

zeesbrat3 · Answer

attachment

anonymous · Answer

Ok. Think with me:

BEF is similar to BAC.


So you just need to use the similarity of triangles rule.
Can you solve it now?

zeesbrat3 · Answer

I know this is a practice test, but I have completely blanked out about this section. Mind working it through with me?

anonymous · Answer

ok.

BA = AC
BE = EF.

EF = BE*AC/BA

can you do it from here?

zeesbrat3 · Answer

Ya, thanks

anonymous · Answer

EF = 72.

BC = CA 
BF = FE 
BF = FE*BC/CA 
BF = 144 


answer: (180-144)*2 + 72*2 = 216 feet 

Here's your answer so you can confirm the result

zeesbrat3 · Answer

I dont have an answer choice for 216...

zeesbrat3 · Answer

Here are my answer choices:
90 feet

 108 feet

 36 feet

 120 feet

anonymous · Answer

oh. I was doing the total lenght of the figure. 

EF = 72
DE = 36

anonymous · Answer

72+36 = 108

zeesbrat3 · Answer

thats what i thought.. i took the original proportion you gave me and checked the answer that came closest, and made the most sense