Question

Factor completely: x2 + 11x + 24

Answer 1

break down the middle term
\[x^2 + 3x + 8x + 24\]
group them
\[(x^2 + 3x) + (8x + 24)\]
factor
\[x(x+3) + 8(x+3)\]
factor again
\[(x+8)(x+3)\]

Answer 2

okay thankyou very much

Answer 3

<tips hat>