Question

is the asymptotes of the following function and the curve lies about them..
f(x)=xsquare2/x-3

Answer 1

@Muskan Is this your question?
\[y=\frac{x^2}{x-3}\]

Answer 2

yess

Answer 3

I think the initial part of the question is missing, Could you post it?

Answer 4

no is it

Answer 5

onlyy

Answer 6

ok, could you tell for what value of x the denominator is zero?

Answer 7

i thnk
(x-3)^2= (x-3)(x-3)
X=3

is it rite??

Answer 8

Is there (x-3)^2 in the denominator?

Answer 9

yes

Answer 10

yeah x=3 is an asymptote

Answer 11

Do you need to plot it also?

Answer 12

thnxx

Answer 13

\[ {x^2 \over (x - 3)^2} = 1+ {(x - 3)^2 - x^2 \over (x-3)^2}\]
y = 1 is your horizontal asymptote