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Mathematics 53 Online
OpenStudy (anonymous):

How do you simplify this?

OpenStudy (anonymous):

\[-4x(x ^{-3}y ^{2})(-2x ^{4}y ^{-3})\]

OpenStudy (valpey):

You are multiplying a number of terms here; some constants, and some exponentiated bases. There is a phrase (alike bases, add exponents). What it means is that for the two different bases, x and y, we can add together all the exponents. So first multiply the constants together and put that in front. Next write and x and sum all the exponents attached to the x's (remember x is the same as x^1). Next do the same for the y's.

OpenStudy (anonymous):

Still a bit confused..

OpenStudy (valpey):

First let's do the constants, what are the constants and what is their product?

OpenStudy (anonymous):

There are none..?

OpenStudy (valpey):

What about -2?

OpenStudy (anonymous):

How?

OpenStudy (valpey):

-4 and -2 are constants or coefficients. You can multiply them together.

OpenStudy (valpey):

That gives us: \[(-2*-4)*x(x^{-3}y^2)(x^4y^{-3})\]

OpenStudy (valpey):

Next, let's group the x's and the y's together.

OpenStudy (valpey):

Remembering that x is the same as x^1, you can add the exponents together for each base, x and y.

OpenStudy (valpey):

\[(-2*-4)(x^1x^{-3}x^4)(y^2y^{-3})\] Good luck!

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