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OpenStudy (anonymous):
Determine the number of solutions of 2x2 + 3x = 0.
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OpenStudy (shayaan_mustafa):
Hi iceyweheniplease7 :)
How are you?
OpenStudy (shayaan_mustafa):
Your equation is look like this,
\[\Large 2x^2+3x=0\]
OpenStudy (hba):
4+3x=0
3x=-4
x=-4/3
OpenStudy (shayaan_mustafa):
It is a two degree equation so it has two solutions.
OpenStudy (anonymous):
IM GREAT :) and how r u?:)
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OpenStudy (shayaan_mustafa):
The highest degree is 2
OpenStudy (shayaan_mustafa):
Fine. Thank you :)
OpenStudy (anonymous):
2x^2+3x=2x(x+3/2)----->x=0 & x=-3/2
OpenStudy (anonymous):
the degree of the equation means nothing as to whether or not it has any solution. anyways...yours has one solution. x=-3/2
OpenStudy (anonymous):
the degree of the equation does tell yo the max number of POSSIBLE zeros. that's about it...
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OpenStudy (shayaan_mustafa):
@hba you are wrong my friend.
OpenStudy (hba):
@Shayaan_Mustafa i missunderstood the question :D
OpenStudy (anonymous):
A plot is attached.
OpenStudy (anonymous):
lol...forgot the trivial solution. Yeah x=0 works too :)
OpenStudy (anonymous):
Thank you for the medal.
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OpenStudy (anonymous):
thanks for the reminder regarding division by zero :)
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