solve: log(x+4)=logx + log4 show work
do you know the log rules for adding two logs?
if not, have a look here first: http://www.mathsisfun.com/algebra/exponents-logarithms.html and then try to attempt your question. If you still have trouble then post where you are getting stuck here and I'll try and help you out.
yes i know the rules. i got to: (x+4/4x)=0 ...is that the right track?
you went one step too far... you probably got to this step first: log(x+4) = log(4x) - correct?
yes
then subtracted to set it equal to zero
ok, so you have log(something) = log(something else) which implies something = something else
yes....
but i need an actual answer.... it's supposed to be 12
you got to this: log(x+4) = log(4x) which implies: x + 4 = 4x now just solve to find x
thank you
yw :)
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