Question

Solve for x.
2x^2-4x+1=0

Answer 1

use quadratic formula
\[\large x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

Answer 2

Is it an equation or simply an expression???
meaning:
\[2x^2 - 4x + 1 \qquad or \qquad 2x^2 - 4x + 1 = 0\quad ?\]

Answer 3

I'm stuck at x = (8+2sqrt2)/4, (8-2sqrt2)/4... is this the simplest form?

Answer 4

fololl lgbasallote formula , a=2 , b= -4 , c=1

Answer 5

Tell me what is a, b and c here by comparing it with standard equation:

\[ax^2 + bx + c = 0\]

Answer 6

can u solve?

Answer 7

i think he just did lol

Answer 8

@derptastic878 factor out

Answer 9

im not sure if you're right but i'll assume you are
\[x = \frac{8 + 2\sqrt 2}{4}\]
\[x = \frac{2(4 + \sqrt 2)}{4}\]
\[x = \frac{4 + \sqrt 2}{2}\]
do the same for the other one

Answer 10

Thanks!

Answer 11

<tips hat>

Answer 12

Can x = (8-2sqrt2)/4 be factored? The 2 is negative.

Answer 13

yes it can :)

Answer 14

2(4-sqrt2) ?

Answer 15

yes that's the numerator

Answer 16

2(4-sqrt2)/2 :D?