Question

i need to see a demo (and probably an explanation) on how to find the maximum/minimum of an equation using derivatives

Answer 1

\[y=x^2\]finding the max/min of a function in calculus means setting the derivative equal to zero\[\frac{dy}{dx}=2x=0\implies x=0\]so that is where our minimum is for x^2 (as if you didn't already know that)

Answer 2

so the minimum value of f(x) is f(0), which is 0

Answer 3

this, of course, works for more complicated functions as well, I just wanted to start basic

Answer 4

to be more precise im trying to find the maximum of \[q = 10te^{-5t}\]

Answer 5

well what's dq/dt ?

Answer 6

i believe it's \[10[e^{-5t} - 5e^{-5t}]\]
correct?

Answer 7

I think you lost a t