if two painters paint two rooms in two hours then how many painters would be required to paint 18 rooms in six hours? explain..how to use proportionality in this?
Think of it as number of rooms per painter per hour or number of rooms per painter-hour.
In the first instance you have two painters working for two hours so that is 4 "painter-hours". If they can paint two rooms with 4 "painter-hours", then we can infer that each room takes two "painter-hours" to complete.
How many painter-hours does it take to complete 18 rooms?
i dont understand it please explain again..sorry
1p-h is a measure of work. We know that one room can be completed with 2 p-h's.
1 guy working for 5 hours might get the same amount of work done that five guys working for 1 hour could do. In each case they complete 5 p-h's of work.
Here's another way to look at it: You have 18 rooms which need to be painted in 6 hours. So you need to paint 3 rooms per hour which is the same as 6 rooms every 2 hours. If 2 painters can paint 2 rooms in 2 hours then how many painters would it take to paint 6 rooms every 2 hours?
6
thank you @Shane_B ...thank you@valpey
Cheers!
Good luck :)
I got the answer as 54.. Am I right?? Just wanted to know..
For this question??
Yes.. I don't know how but I use the proportionality and chain rule for this..
That answer doesn't even make logical sense :)
The answer is 6!
54 painters would paint 27 rooms in the first 2 hours!
I check it once more.. We have to paint 18 rooms in 6 hours..
Maybe you've misread the question :)
I have just solved like this using proportionality....: I show you..
Yeah I got it, I found the mistake..
I think you're over-complicating this :)
Let the painters required be x So, More rooms, More Painters (Direct Proportion) More Hours, Less Painters (Indirect Proportion) So, Rooms Proportion is : 2:18 Hours Proportion is : 6:2 And Painter Proportion is : 2:x So, \[\frac{2}{18} \times \frac{6}{2} = \frac{2}{x}\] \[x=6..\]
That makes more sense!
12 ???
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