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OpenStudy (anonymous):
Factorize first numerator and denominator..
OpenStudy (anonymous):
Take 4 common from the numeration and then factorize it, this will be simple to factorize..
OpenStudy (anonymous):
for the numerator i got 4(x-6)(x-2) but how are you suppose to simplify the denominator when 17 cant be simplified?
OpenStudy (anonymous):
Denominator is:
\[= (3x +1)(x-6)\]
OpenStudy (anonymous):
[4(x-6)(x-2)/ (x-6)(3x+1)]=0
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OpenStudy (anonymous):
how did you guys get the denominator?
OpenStudy (anonymous):
Cancel what you can cancel and then tell me what you are left with??
OpenStudy (anonymous):
It is simple:
See, when:
\[a \ne 1\]
Then we make the factors of ac..
that is : 3*(-6) = -18
Getting??
OpenStudy (anonymous):
Ok I see what your saying
OpenStudy (anonymous):
In numerator after taking 4 common the coefficient of x became 1 but in denominator coefficient of x is not 1 but 3..
In this case we multiply coefficient of x with constant term that is c..
So, 3*(-6) = 18
Factors of 18 can be 18 and 1..
Can you proceed further??
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