Given:-:-$$\alpha \beta $$ are the roots of the equation $$x^2+px+q=0$$ then the value of $$\left[ {\alpha \over \beta}+{\beta \over \alpha} \right]$$ is equal to:-

Question

Given:-:-$$\alpha  \beta $$ are the roots of the equation $$x^2+px+q=0$$ then the value of $$\left[ {\alpha \over \beta}+{\beta \over \alpha} \right]$$ is equal to:-

anonymous · Answer

You can rewrite what you have to find:

$$= \frac{\alpha^2 + \beta ^2}{\alpha. \beta}$$

anonymous · Answer

$$\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha \beta}=\frac{(\alpha+\beta)^2-2 \alpha \beta}{\alpha \beta}$$

jiteshmeghwal9 · Answer

Oh! I got it thanx a lot @waterineyes & @mukushla

anonymous · Answer

Welcome dear..

jiteshmeghwal9 · Answer

The only thing is we have to put the values of alpha & beta in the equation, isn't it???

anonymous · Answer

yes thats right

anonymous · Answer

Sum of roots :

$$\alpha + \beta = -p$$

Product of roots:

$$\alpha. \beta = q$$

Just plug in the formula that mukushla gave you..

jiteshmeghwal9 · Answer

k!