Question

Just Curious

Answer 1

*curious c;

Answer 2

lol thanks

Answer 3

lol np and it depends on the problem. It typically depends on the problem you are working on but it's almost guaranteed that if you are working on an algebraic problem, you use pemdas.

Answer 4

@rebeccaskell94: Do you know an example where it doesn't work? I'm trying to think of one...

Answer 5

\[x(x+3)+x=x(x+3+1)=x(x+4)\]in this case we factored first... not sure if that counts as avoiding pemdas, but I think so

Answer 6

this is actually a pretty tough question lol

Answer 7

In my mind that example still uses PEMDAS

Answer 8

@TuringTest it still uses the P of PEMDAS right?