Question

For what real values of k are the roots of kx^2+3x-2=0 not real numbers?

Answer 1

the roots will not be real if discriminant is negative.
discriminant of this equation is : D = 9+8k
so we need D<0 . So
9+8k<0
8k<-9
k<-9/8

Answer 2

for a general 2º degree polinomial:
\[ax ^{2}+bx+c\]
the Discriminant formula is:
\[D=b ^{2}-4ac\]
in your case: a=k, b=3, c=-2. So
\[3^{2}-4k(-2)=9+8k\]

Answer 3

Thanks!

Answer 4

yw