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Mathematics 19 Online
OpenStudy (anonymous):

What is the remainder when (2x4 – 3x3 + x2 – 3x – 15) ÷ (x – 2) ?

OpenStudy (amistre64):

by which method does this have to be accomplished?

OpenStudy (anonymous):

between on of these 2x – 2 3x + 2 4x + 2 2x + 6

OpenStudy (amistre64):

the simplest thing would be to just divide it thru .....

OpenStudy (anonymous):

alright do it for me?

OpenStudy (amistre64):

do it for you? nah, i dont need the practice ....

OpenStudy (anonymous):

im trying to learn thats all

OpenStudy (amistre64):

then i can walk you through it

OpenStudy (anonymous):

yes that would be perfect

OpenStudy (amistre64):

do you remember doing longhand division back in the 3rd grade? same concept

OpenStudy (anonymous):

okay

OpenStudy (amistre64):

____________________________ x – 2 ) 2x4 – 3x3 + x2 – 3x – 15 just focus on the first parts; the number your looking to start out with will be 2x4/x 2x4/x = 2x3 2x3 ____________________________ x – 2 ) 2x4 – 3x3 + x2 – 3x – 15 now multiply the leftside by the top and subtract the results; then repeat as needed

OpenStudy (anonymous):

okay thanks how see it now

OpenStudy (amistre64):

2x3 (x-2) = 2x4 -4x3 2x3 ____________________________ x – 2 ) 2x4 – 3x3 + x2 – 3x – 15 -(2x4 -4x3) ----------- x3 (bring down the rest) 2x3 ____________________________ x – 2 ) 2x4 – 3x3 + x2 – 3x – 15 -(2x4 -4x3) ----------- x3 + x2 – 3x – 15 ; and repeat

OpenStudy (amistre64):

can you give me the next top value that we would need? remember, just focus on the first parts

OpenStudy (anonymous):

I got it

OpenStudy (amistre64):

ok, good luck ;)

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