What is the remainder when (2x4 – 3x3 + x2 – 3x – 15) ÷ (x – 2) ?
by which method does this have to be accomplished?
between on of these 2x – 2 3x + 2 4x + 2 2x + 6
the simplest thing would be to just divide it thru .....
alright do it for me?
do it for you? nah, i dont need the practice ....
im trying to learn thats all
then i can walk you through it
yes that would be perfect
do you remember doing longhand division back in the 3rd grade? same concept
okay
____________________________ x – 2 ) 2x4 – 3x3 + x2 – 3x – 15 just focus on the first parts; the number your looking to start out with will be 2x4/x 2x4/x = 2x3 2x3 ____________________________ x – 2 ) 2x4 – 3x3 + x2 – 3x – 15 now multiply the leftside by the top and subtract the results; then repeat as needed
okay thanks how see it now
2x3 (x-2) = 2x4 -4x3 2x3 ____________________________ x – 2 ) 2x4 – 3x3 + x2 – 3x – 15 -(2x4 -4x3) ----------- x3 (bring down the rest) 2x3 ____________________________ x – 2 ) 2x4 – 3x3 + x2 – 3x – 15 -(2x4 -4x3) ----------- x3 + x2 – 3x – 15 ; and repeat
can you give me the next top value that we would need? remember, just focus on the first parts
I got it
ok, good luck ;)
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