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2x^2 + 2y^2 + 2x - 4y = -1 find the standard form of the circle
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Do you know how to use completing the square? Because this is what you have to do in this case.
Oh and divide by two first of course. makes it a bit easier.
he's right, should be no problem solving now
\[ k: f(x,y)=(x+\frac{1}{2})^2+(y-1)^2= \frac{3}{4} \] possible that I have done a careless mistake somewhere, but this is what I get.
thanks
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