Question

Which Pair Of Points Defines A Line With A Slope Of -4/3

Answer 1

The Anwer Has To Be Out Of
(-1, 6) and (-4, 10)
B. (6, -1) and (-4, 10)
C. (-1, 6) and (10, -4)
D. (6, -1) and (10, -4)

Answer 2

Help @Ganpat

Answer 3

slope (m) = rise/run = (y2 - y1)/ (x2 - x1)...

now can u check, with this formula ??

Answer 4

iM Thinking D. What Do You Think Ganpat

Answer 5

ha ha, u r smart dude.. LOL

Answer 6

-4/3 = (y2 - y1)/ (x2 - x1)

A = -4/3
B = - 11/10
C = - 10/ 11
D = -3/4..

Now, u try..

Answer 7

Ganpat Try This 1 On 4 Size Lol
Which of these pairs of points defines a line with a slope of -1?
A. (3, 10) and (3, 5)
B. (3, 10) and (5, 3)
C. (10, 3) and (15, -2)
D. (10, 3) and (3, 5)

Answer 8

i tried.. now its ur turn.. :-p.. LOl..

Answer 9

A. (3, 10) and (3, 5)=0,-5
B. (3, 10) and (5, 3)=-2,7
C. (10, 3) and (15, -2)=-5,5
D. (10, 3) and (3, 5)=7,-2
Am iRight? Lol

Answer 10

well, the answer is C... (-2-3)/ (15-10 ) = -5/5 = -1...

Answer 11

Yes iGot iT

Answer 12

u r learning fast... Gooooooooddd !!!

Answer 13

But What iF iT iN Reverse Like.......
Define A Line A Slope Of 2/3
A. (2, 6) and (3, 0)
B. (6, 2) and 3, 0)
C. (6, 2) and (0, 0)
D. (2, 6) and (0, 0)

Answer 14

A. (2, 6) and (3, 0)=-1,6
B. (6, 2) and 3, 0)=3,2
C. (6, 2) and (0, 0)=6,2
D. (2, 6) and (0, 0)=2,6