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Mathematics 10 Online
OpenStudy (anonymous):

Find the first and third quartiles of the data set. 432, 455, 280, 216, 353, 387, 119, 293, 241, 460, 389, 121, 142

OpenStudy (anonymous):

do the same that I did before to calculate the first quartile. And for third quartile use this formula: 3rd quartile = 3(n+1)/2 th term

OpenStudy (anonymous):

i did mistake 3rd quartile= 3(n+1)/4 th term

OpenStudy (anonymous):

how would i write that as my answer ?

OpenStudy (anonymous):

first arrange the data in ascending order, and find n

OpenStudy (anonymous):

how do i do that?

OpenStudy (anonymous):

in ascending order, 119,121,142,216,241,280,293,353,387,389,432,455.460

OpenStudy (anonymous):

ok an what doi do next

OpenStudy (anonymous):

now count the number of data which is n. in this case n = 13

OpenStudy (anonymous):

is that for the 1st an the 3rd

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