Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

If f(x) = 2x2 + 2, find f(5). 102 52 22 −1.5

OpenStudy (anonymous):

does x=5

OpenStudy (anonymous):

I think so

OpenStudy (diyadiya):

Just plug in the value of x in the equation f(5) = 2(5)^2 + 2

OpenStudy (anonymous):

can you solve it?

OpenStudy (anonymous):

thts not our job its yours

OpenStudy (diyadiya):

Where do you find the difficulty?

OpenStudy (diyadiya):

i just replaced x with 5 \[f(5)= 2(5)^2 +2\]

OpenStudy (diyadiya):

What is \(\large 5^2 \) ?

OpenStudy (anonymous):

25

OpenStudy (diyadiya):

f(5)= 2(25) + 2 now what is 2 x 25 ?

OpenStudy (anonymous):

50

OpenStudy (theviper):

ans is 102 first put the value of x in eq that is 5 & get ur ans:) @Diyadiya is correct:)

OpenStudy (diyadiya):

So f(5) = ? @Megan10118765

OpenStudy (anonymous):

thank you! :)

OpenStudy (diyadiya):

@TheViper 102 is not the answer, Sorry

OpenStudy (theviper):

typo mistake 52

OpenStudy (anonymous):

so its 52?

OpenStudy (theviper):

yes

OpenStudy (theviper):

2(5)^2+2 =2*25+2 =50+2 =52

OpenStudy (theviper):

@Megan10118765

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Countless7Echos: Ah trying out the whole T.V girl drawing :p (I love drawing eyes)
1 hour ago 11 Replies 6 Medals
kaelynw: starting to draw a hand
2 days ago 16 Replies 2 Medals
Twaylor: Rate it :D (Took 2 days)
3 days ago 7 Replies 0 Medals
XShawtyX: Art, Short Writing Assignment: Imagining Landscapes
1 day ago 7 Replies 1 Medal
XShawtyX: Chemistry, Help ud83dude4fud83cudffe
4 days ago 13 Replies 1 Medal
kaelynw: tried a lil smt, the arm is off but i like the other stuff
4 days ago 27 Replies 3 Medals
kaelynw: art igg
4 days ago 14 Replies 1 Medal
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!