Question

Can't remember how to solve problems like this... Pic attached in comments :)

Answer 1

Since 2 = √ 2 * √ 2
Then do you know what to do with the denominator?

Answer 2

Do we have to simplify it or ...?

Answer 3

I think so, the paper I'm doing says to just solve it

Answer 4

Since the question has no variable, just simply the fraction! Can you?

Answer 5

I don't know, i remember doing a problem like this, i just how to simplify it

Answer 6

According to @Chlorophyll ,
\[\frac{\sqrt32}{\sqrt2} = \frac{\sqrt3\sqrt2\sqrt2}{\sqrt2} \]Now, cross out the common factor, what do you get?

Answer 7

\[\sqrt{3}\sqrt{2} ??\]

Answer 8

Unless of course, you meant:
\[\frac{\sqrt{32}}{\sqrt{2}}\]
In which case you can combine the square root:
\[\sqrt{\frac{32}{2}}\]

Answer 9

@Callisto That's how i learned it :) Could you explain how you got to that?

Answer 10

But yes,
\[\frac{\sqrt{3}*2}{\sqrt{2}}=\frac{\sqrt{3}\sqrt{2}\sqrt{2}}{\sqrt{2}} =\sqrt{3}\sqrt{2} = \sqrt{3*2} \]

Answer 11

Actually, @Chlorophyll has explained it...
2 = √ 2 * √ 2
When you simplify the numerator and denominator, you'll get that.
But it's not done yet!
\[\sqrt{a}\sqrt{b} = \sqrt{ab}\]
Now, you got √ 3 * √ 2 , can you further simplify it?

Answer 12

\[\sqrt{3*2} \] like @Valpey said

Answer 13

Multiply 3 by 2, what do you get?

Answer 14

6

Answer 15

Yes, so for \(\sqrt{3\times 2} \), can you simplify it?

Answer 16

\[\sqrt{6} ??\]

Answer 17

Yes.

Answer 18

I'm not trying to be annoying, but I'm really confused on these, i found this whiteboard site, that lets you see other peoples drawings in live time. Would you mind writing it out step by step for me?

Answer 19

heres the link
http://scriblink.com/index.jsp?act=phome&roomid=273&KEY=3FBC9E49B75FA5901EBFD133208E9E29

Answer 20

@MissPink all you do is to read and repeat what Callisto has posted!

Answer 21

ok

Answer 22

Im just confused on how you get