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OpenStudy (anonymous):
would you use substitution or elimination to solve each of the following systems?
a. {y=2x+1
y=3x-2
b. {x=3y-1
3x+5y+4
c.{4x-3y=4
3x+5y=16
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OpenStudy (anonymous):
1 st one i think both methods are cool
OpenStudy (anonymous):
2nd sub nd third elimination
OpenStudy (anonymous):
how are they substitution and elimination tho?
OpenStudy (anonymous):
substitution let the value of y in the A) 1st equation be the value of y in the second equation
OpenStudy (anonymous):
u kno sub method it means u put value of variable obatained from an eq into another eq......
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OpenStudy (anonymous):
sorry im new to all this algebra stuff lol
OpenStudy (anonymous):
like check the secon eq......u have the eqn for x...... nd u can put that easily in 3x+5y+4
OpenStudy (anonymous):
wow um ther's an = missing
OpenStudy (anonymous):
opps b. {x=3y-1
3x+5y+4
OpenStudy (anonymous):
i think it's 3x+5y = 4
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OpenStudy (anonymous):
omg i just did that ughh lol
OpenStudy (anonymous):
so what about the third problem how is it elimination?
OpenStudy (anonymous):
coz it's not substitution.............it's kinda hard to isolate a variable(x/y) from either of the eqns........
OpenStudy (anonymous):
oh okay thanks :)
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