Question

factor the expression and use fundamental identities to simplify.
sin^2xcsc^2x-sin^2x

Answer 1

hmm will knowing \[\large \csc^2 x = \frac{1}{\sin^2 x}\]
help?

Answer 2

how is the soution cos^2x

Answer 3

\[\Large \sin^2 x \times \frac{1}{\sin^2 x} - \sin^2 x\]
do you agree with this?

Answer 4

yes

Answer 5

and what's \[\sin^2 x \times \frac{1}{\sin^2 x}\]

Answer 6

i thought we could cancel them :o

Answer 7

yup...so what would it be?

Answer 8

1? but the answer is cos^2x :o

Answer 9

lol we'll get there :p

Answer 10

\[(\sin^2 x \times \frac{1}{\sin^2 x}) - \sin^2x\]
\[\implies (1) - \sin^2 x\]
agree?

Answer 11

ywa

Answer 12

so what's \(1 - \sin^2 x?\)

Answer 13

im guessing cos^2x LOL but i dont see it in my identities

Answer 14

\[\sin^2 x + \cos^2 x = 1\]
do you see that in your identities?

Answer 15

ohhh justi kidding! Pythagoream identities

Answer 16

that was pythagorean identity? lol...fancy terms =)))

Answer 17

yeah ahaha