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If the equations x^2+px+q=0 and x^2+bx+c=0 have 1 common root, then it is equal to?? Ans.-[(q-c)/(p-b)]
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x^2+px+q-(x^2+bx+c)=px+q-bx-c=0 x=-[(q-c)/(p-b)]
let a be common root.. then: a^2 +pa + q =0 and a^2 +ab +c=0 subtracting both : you get a = your ans
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