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Mathematics 59 Online
OpenStudy (anonymous):

a train runs between two stations stopping at each. Its velocity V km/min, t minutes after leaving the first station, is given by v = 0.12t(6-t)

OpenStudy (anonymous):

find the time taken to travel between the two stations

OpenStudy (amistre64):

if something is stopped, its velocity is 0 right?

OpenStudy (anonymous):

yes

OpenStudy (amistre64):

then for which ts does V = 0?

OpenStudy (anonymous):

for t=0 and t=6 obviously...

OpenStudy (amistre64):

obviously lol

OpenStudy (cwrw238):

so after first starting it stops again after 6 minutes

OpenStudy (amistre64):

i was going to say 360 seconds, but 6 minutes sounds adequate

OpenStudy (cwrw238):

yup - lol

OpenStudy (anonymous):

yup...the time difference between the two stations is 6mins...when the train travels at Vkm/min.

OpenStudy (cwrw238):

there you go

OpenStudy (anonymous):

LOL @Akshat4-10 and @cwrw238 for impersonating me hahahas thanks guys ;)

OpenStudy (anonymous):

so for this question how would we find ii- the maximum positive velocity attained iii- the distance between the two stations

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