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OpenStudy (anonymous):
a train runs between two stations stopping at each. Its velocity V km/min, t minutes after leaving the first station, is given by v = 0.12t(6-t)
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OpenStudy (anonymous):
find the time taken to travel between the two stations
OpenStudy (amistre64):
if something is stopped, its velocity is 0 right?
OpenStudy (anonymous):
yes
OpenStudy (amistre64):
then for which ts does V = 0?
OpenStudy (anonymous):
for t=0 and t=6 obviously...
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OpenStudy (amistre64):
obviously lol
OpenStudy (cwrw238):
so after first starting it stops again after 6 minutes
OpenStudy (amistre64):
i was going to say 360 seconds, but 6 minutes sounds adequate
OpenStudy (cwrw238):
yup - lol
OpenStudy (anonymous):
yup...the time difference between the two stations is 6mins...when the train travels at Vkm/min.
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OpenStudy (cwrw238):
there you go
OpenStudy (anonymous):
LOL @Akshat4-10 and @cwrw238 for impersonating me hahahas
thanks guys ;)
OpenStudy (anonymous):
so for this question how would we find
ii- the maximum positive velocity attained
iii- the distance between the two stations
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