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What is the equation of the line of symmetry for the graph of y = 3(x + 2)2 - 4?
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Write the equation in vertex form. y = 3x² + 12x - 2 = 3(x² + 4x) - 2 = 3(x² + 4x + (4/2)² - (4/2)²) - 2 = 3(x² + 4x + 4) - 3*4 - 2 = 3(x + 2)² - 14
Answer= -14
a. x = -4 b. x = -2 c. x = 2 d. x = 3
Hint : line of symmetry goes thru vertex
|dw:1342101930168:dw|
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y = 3x² + 12x - 2 = 3(x² + 4x) - 2 = 3(x² + 4x + (4/2)² - (4/2)²) - 2 = 3(x² + 4x + 4) - 3*4 - 2 = 3(x + 2)² - 14 The equation for the axis of symmetry is (x + 2) = 0, that is, x = -2. The axis passes through the vertex of the parabola; its coordinates are (-2, -14)
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