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OpenStudy (anonymous):
3x - 2 - 2x + 1 = x - 1 = 2 - 1 = 1
yea.
by the way i think i gave you the wrong explaination for the first one ._.
but if you get -19, you are right lol
OpenStudy (anonymous):
If f(x) = 1/3x − 2 and g(x) = −2x − 1, find (f • g)(9)
suppose to be (1/3 x - 2)(-2x-1) = -1/3 (x - 6)(2x + 1)
-1/3 (9 - 6)(18 + 1) = - 19
OpenStudy (anonymous):
haha okay thanks
OpenStudy (anonymous):
If f(x) = 3x + 1 and g(x) = 2x − 4, find f[g(2)].
25
4
0
1
OpenStudy (anonymous):
g(2) first then f(g(2)) :x
2(2) - 4 = ?
then 3(?) + 1
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OpenStudy (anonymous):
I got 0 for 2(2)-4
OpenStudy (anonymous):
yup then 3(0) + 1
OpenStudy (anonymous):
okay so the answer would be 1
OpenStudy (anonymous):
If f(x) = −3x − 3 and g(x) = 2x + 1, find f/g (−2).
−3
3
−1
1
OpenStudy (anonymous):
hmm
\[\frac{-3x-3}{2x+1}\]then sub x = -2
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OpenStudy (anonymous):
i got 3 for -3(-2)-3
OpenStudy (anonymous):
and -3 for 2(-2)+1
OpenStudy (anonymous):
then 3/(-3)~
OpenStudy (anonymous):
so the answer would be -1 right
OpenStudy (anonymous):
If f(x) = 1/2x + 2 and g(x) = −3x − 1, find g[f(4)].
−19
11
−13
−11
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OpenStudy (anonymous):
find f(4) then g(f(4))
OpenStudy (anonymous):
I got -13 is that correct
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
If f(x) = 2x + 1 and g(x) = −2x − 3, find (f + g)(−1).
2
4
−2
−8
OpenStudy (anonymous):
2x + 1 - 2x - 3
x = -1
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