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Solve. x+4=-4/x
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\[x+4=-\frac{4}{x}\]?
Yeah, that's the equation?
multiply both sides by \(x\) to clear the fraction you get \[x(x+4)=-4\] then solve the quadratic equation you good from there?
I have no clue.. what you just did. i'm confused
Oh wait! It's -2?!
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i multiplied by \(x\) to get rid of the fraction
its really simple x*(x+4)= x*(-4/x)
on rhs x will be canceled by x
\[(x+4)=-\frac{4}{x}\] \[x\times (x+4)=-\frac{4}{x}\times x\] \[x(x+4)=-4\] \[x^2+4x=-4\] \[x^2+4x+4=0\] etc yes it is \(x=-2\)
you do not "factor" before you put everything on one side of the equal sign it is \[(x+2)^2=0\implies x=-2\] as you said
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