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OpenStudy (anonymous):
Implicitly differentiate cosθ=x/L (with respect to t) i get -sinθdθ/dt= not sure how to work x/L ty
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OpenStudy (anonymous):
u mean theta=theta(t) and x=x(t) ??
OpenStudy (anonymous):
θ and x are both functions of t
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
treat x just like theta
OpenStudy (anonymous):
ahhh x is the function of t, so 1/Ldx/dt
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OpenStudy (anonymous):
exactly
OpenStudy (anonymous):
I was thinking of quotient rule--now I get it thanks
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