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log2+logx=log32
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does x=30? that seems far too easy.
2x = 32 x = 16
log 2x = log 32 2x = 32 x = 16
Use: \[Loga + Logb = Log(ab)\]
\[\implies Log2x = Log32 \implies 2x = 32 \implies x = 16\]
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So it was too easy to be true. So when it's logs it multiplys together? in this format that is.
I have written the formula above.. If the question is given in that form then you can use this..
you need to know laws of logs log a + log b = log ab log a - log b = log a/b and log a^n = n log a
Thank you. you were both a very big help but cwrw238 was a little clearer.
\[Loga + Logb = Log(ab)\] \[Loga - Logb = Log(\frac{a}{b})\] \[Logx^n = n.Logx\]
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