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y varies jointly with p and q. When p = 5 and q = 2, y = 80. Find y when p = 4 and q = 5.
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"y varies jointly with p and q" means that y = kpq for some (not known yet) constant k
"When p = 5 and q = 2, y = 80" this means that y = kpq becomes 80 = k*5*2 which turns into 80 = 10k
Solve that for k and tell me what you get
8?
yes good
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So y = kpq turns into y = 8pq
so its 8*4*5
Last part: Find y when p = 4 and q = 5 Plug in p = 4 and q = 5 to go from y = 8pq to y = 8*4*5 y = ??
yes
thank you
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