Question

Solve for x.
log2x + log(x-1) = log6x

Answer 1

When you add logs together, it is the same as the log of the product of the terms so:
\[log(a)+log(b) = log(a*b)\]
Also, you cannot take the log of zero or a negative number.

Answer 2

Your problem is of the form:
\[log(a)+log(b)=log(c)\]
You can simplify with:
\[log(a*b)=log(c)\]
And as long as you make sure neither c or a*b are <= 0 you can say:
\[a*b=c\]

Answer 3

Thank you!! This helped a lot!

Answer 4

Oh, good.