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OpenStudy (anonymous):
Let f(x) = x + 8 and g(x) = x2 - 6x - 7. Find f(g(2)).
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OpenStudy (lgbasallote):
first what is g(2)?
OpenStudy (anonymous):
???
OpenStudy (lgbasallote):
what do you mean "????"
OpenStudy (anonymous):
your question said what is g(2) that how the poblem was given
OpenStudy (anonymous):
First you must find g(2) by putting into the equation for g(2). Then you would take the step as to put what g(2) = into the f(x) equation.
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OpenStudy (anonymous):
By putting 2 into the equation for g, excuse me. Its a multi-step equation.
OpenStudy (anonymous):
When you see g(2), that means solve g(x) where x = 2.
\[\Large g(x) = x^{2}-6x-7\]
\[\Large g(2) = 2^{2}-(6*2)-7= ?\]
OpenStudy (lgbasallote):
f(g(2) ) means you find g(2) then substitute that to x in f(g(2) )
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
Note: Alternatively you could solve it all at once (but that may confusing right off the bat):
\[\Large f(g(2)) = (x^{2}-6x-7)+8 = x^{2}-6x+1\]
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OpenStudy (anonymous):
What did you get for g(2)?
OpenStudy (anonymous):
-15
OpenStudy (anonymous):
Correct.
Since g(2)=-15, that means f(g(2)) = f(-15).
\[\Large f(x) = x+8\]
\[\Large f(-15) = -15+8 = ?\]
OpenStudy (anonymous):
Let f(x) = x + 8 and g(x) = x2 - 6x - 7. Find f(g(2)).
first find g(2) then once you find that
plug that to f(x)
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