Question

The base of a triangle is fixed and the ratio of the lenghts of the the other two sides is constant . Find the locus of the vertex joining the other two sides.

Answer 1

\[\sqrt{x^2+y^2}=k \sqrt{(x-a)^2+y^2}\]

Answer 2

looks perfect !!

Answer 3

square on both sides n try to simplify...

Answer 4

yeahh checked with my calc :)
but have trouble turning that into circle form..

Answer 5

got it...
gimme sometime to post the solution