Write the equation of the line that is perpendicular to the line y = 3/2x + 4 and passes through the point (−6, 3)

y =3/2 x − 1
y = 3/2x + 3
y = −2/3x − 1
y = −2/3x + 3

Question

Write the equation of the line that is perpendicular to the line y = 3/2x + 4 and passes through the point (−6, 3)

y =3/2 x − 1
 y = 3/2x + 3
y = −2/3x − 1
 y = −2/3x + 3

lgbasallote · Answer

hmm which do you think is it

anonymous · Answer

idk, I've been workin on this for like 20mins, I just dont get it -.-

anonymous · Answer

y = (3/2)x + 4

The perpendicular line will have the negative reciprocal slope. It will be of the form:
y = -(2/3)x + b

Substitute the given point for the x and y values and solve for b.

anonymous · Answer

y = -2x/3 + 6 <==================> ANSWER

anonymous · Answer

Thats the answer if you were doing it another way but it seems by the looks of it your doing the opposite so the answer is D  y = −2/3x + 3

anonymous · Answer

Tell me if that helps;)