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Mathematics 12 Online
OpenStudy (anonymous):

You and two friends (Adam and Alana) will only play a game if it is fair for all three of you. The game your friend has proposed is to roll two number cubes (numbered 1-6) and find the sum. If the sum is from 1-4 you get the point, 5-8 Adam gets the point, and 9-12 Alana gets the point. Is this game fair for the three of you? Who has the best advantage?

OpenStudy (anonymous):

2 cubes, it means the maximum sum you can get is 12. You are 3 friends so 12/3 = 4 if you get the 1-4, your friend the 5-8 other friend 9-12 Both have 4 numbers. HOWEVER, is impossible to roll 2 dices and the sum = 1, you you actually have 2-4 = 3 chances. Answer: Your friends have the best advantage

OpenStudy (anonymous):

It ask me which one has the better advantage then it will let me choose me one or the other of my friends or no one. It wont let me choose both of them..

OpenStudy (anonymous):

btw im assuming both dices are not addicted. (which means the probability of giving any number from 1 to 6 is the same) there is no further data that allows you to decide wich one has the best advantage cause both are equal. The only one that cant win is you

OpenStudy (anonymous):

I will give a hint. The idea here is to calculate the probabilities for each event. You should then add the probabilities that the sum is 1,2,3 or 4 and do the same with the other two cases (sum 5,6,7 or 8, and sum 9,10,11 or 12). The game is fair if and only if each one of these sets has the same probability (i.e 1/3 each).

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

Oops. Its the guy that stays with the 5-8 numbers

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