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can I have some help with this one? Factor completely 24x^2+30z-9.
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Looks like you can factor out the \(3\).
Ok so would it be 3(8z^2+10z-3)
Yep, but it should be \(8x^2 \) instead of that z coming in.
oh yea sorry about that lol. so thats it?
are you sure both x and z are in equation........?
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so you get -24. two factors of -24 which add up to 10: 6+4... does it matter whether or not the factors are positive or negative? @nitz sorry that was a typo.
wait ,,,,,,firstly what is the exact equation to be factorised???
24x^2+30x-9..... sorry about the confusion.
ok
\[3(8x ^{2}+10x-3)=3(8x ^{2}+12x-2x-3)=3{4x(2x+3)-1(2x+3)}\]
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sorry there is a bracket 3{4x(2x+3)-1(2x+3)} 3(4x-1)(2x+3)
didnt get??????
no I got it, thanks for your help!
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