Question

how do you write in standard form, an equation of the line passing through (-2,-2) with a slope of -8, how do i find the y-intersect?

Answer 1

Hint:
y = mx + b
(x,y) = (-2,-2)
m = -8

b = y-intercept

Answer 2

You can use the point slope form formula to find the y intersect.
Use y =mx+b
To find b, which is our y-intersect substitute our point (-2,-2) into our equation
y=mx+b

-2=-8(-2) + b
-2=16 +b
-2-16=b
-18=b
b = -18
so our y-intersect that passes through the point (-2,-2) with a slope of -8 would be (0,-18)

Now we have b we can turn it into standard form
y = -8x + -18
8x + y = -18

Answer 3

thank you