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Mathematics 12 Online
OpenStudy (anonymous):

compute the Derivative y=ln(lnx)

OpenStudy (australopithecus):

use chain rule g(x) = ln(x) g'(x) = 1/x s(x) = ln(x) s'(x) = 1/x chain rule is simply: g'(s(x))*s'(x) so we have 1/(ln(x)) * 1/x

OpenStudy (australopithecus):

thus 1/xln(x)

OpenStudy (australopithecus):

is the derivative

OpenStudy (anonymous):

thank you.

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