Mathematics
13 Online
OpenStudy (anonymous):
Find Roots : 4x^3+16x^2-9x-36=0
sum of two of the roots =0.
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OpenStudy (anonymous):
Use the factor theorem to find the first root
OpenStudy (anonymous):
pls use sum and product of roots properties.
OpenStudy (anonymous):
let the two roots be \[\alpha &\]
OpenStudy (anonymous):
Roots : p,q,r
p+q+r = -b/a
pq+qr+rp= c/a
pqr = -d/a
OpenStudy (anonymous):
ok so a+b+c = -16/4=-4
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OpenStudy (anonymous):
as a+b=o c= -4
OpenStudy (anonymous):
nw
(+4) is a factor of the given polynomial ryt
OpenStudy (anonymous):
i mean (x+4)
OpenStudy (anonymous):
no factors
OpenStudy (anonymous):
i want it only from the sum and product
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OpenStudy (anonymous):
ok i got it
OpenStudy (anonymous):
thanks for your efforts.
OpenStudy (anonymous):
nw if u divide the given polynomial by (x+4) u will get a quadraitic equation de if u split de middle term u will get the odr roots
OpenStudy (anonymous):
ok i tried to my stndrd :)
OpenStudy (anonymous):
In which class are you studying?
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OpenStudy (anonymous):
10th
OpenStudy (anonymous):
u?
OpenStudy (anonymous):
just passed 10th
OpenStudy (anonymous):
so intrmediate 1st yr?
OpenStudy (anonymous):
cant say now
everything is new now
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OpenStudy (anonymous):
y so?
OpenStudy (anonymous):
course seems to be very different.
OpenStudy (anonymous):
that you have studied in 9th, was just an intorduction. In 11 its full detailed.
OpenStudy (anonymous):
what result you got?
OpenStudy (anonymous):
we'll get it only aftr 10th, cce ryt!