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Solve \[\frac{y^2+x^3}{x^6-3x^3-y^4}\] if \[6(log_y x+log_x y)=13\] and \[1
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\[\log_b a = \frac{1}{log_a b}\]
Maybe log_x y = 1/(log_y x)
Snap!
Kind of messy, though....
It seems to be complicated
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may be that : @asnaseer sir can give us a correct way
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this is a challenge question from my homework, and it's hard
hmn ... challenge question .. not a challenge question but yes it is complicated
both @mathslover and @estudier have pointed to the correct first step here
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it is not as complicated as you might think
Just seems like a lot of messy numerical calculation at the moment.......
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