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(x^2+10x+16)/(x+2)
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factor out the numerator first. what do you get?
Factorise (x+8)(x+2)/(x+2) =(x+8)
\[\large{\frac{x^2+10x+16}{x+2}}\] \[\large{\frac{x^2+8x+2x+16}{x+2}}\] \[\large{\frac{x(x+8)+2(x+8)}{x+2}}\] \[\large{\frac{(x+2)(x+8)}{x+2}}\] \[\large{x+8}\]
got it now ?
yes
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thank you
ur welcome also : \[\Huge{\mathbb{Welcome}\textbf{To }\mathbb{Open}\textbf{Study}}\]
i hope you really got that annej ;)
i do
:D gr8
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but i do have a similar problem that i dont understand
You can ask there as a new question i have to go some body will help u soon
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