When I took e^ to both sides the logs went away...can you solve for x now?
OpenStudy (anonymous):
d?
OpenStudy (anonymous):
Did you even try?
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OpenStudy (anonymous):
another way to view this is that log is a one to one function, so if
\[\log(\text{something})=\log(\text{something else})\] then
\[\text{something}=\text{something else}\]
OpenStudy (anonymous):
uhm yess i did. i added+5 to both sides
OpenStudy (anonymous):
\[−5x=10−3x \]\[−5x+5x=10−3x +5x \]\[0=10+2x \]
OpenStudy (anonymous):
Subtract 10 to both sides and divide by 2....what do you get now?
OpenStudy (anonymous):
-4
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OpenStudy (anonymous):
Do you know how to add subtract divide and multiply?
OpenStudy (anonymous):
dont try me
OpenStudy (anonymous):
of course i do
OpenStudy (anonymous):
You should be able to get the answer from where I left of. you only have to do two steps. subtract and divide.
OpenStudy (anonymous):
i get 0!!
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