Question

y=(2x^2)/(3x^2-16)

What is the horizontal asymptote for the above function?

y = _____

Answer 1

\[y = \frac{2x^2}{3x^2 - 16}\]

Do you know how to find asymptotes in general?

Answer 2

no @failmathmajor

Answer 3

To find the horizontal asymptotes, find the terms with the largest powers in the numerator in denominator. In this case, it's "2x^2" in the numerator and "3x^2" in the denominator. If they have the same power, the horizontal asymptote is just a line that is defined by the ratio of the coefficients of those terms. So 2/3

Answer 4

oh ok thank you!