Question

Simple radical question

Answer 1

\[\sqrt{6x}\times \sqrt{15x}\]

Answer 2

what happens?

Answer 3

Hello

Answer 4

Hello

Answer 5

remember always that :
\[\sqrt{a}*\sqrt{b}=\sqrt{ab}\]
can u do this now ?

Answer 6

try to convert it into this form \(\sqrt{ab}\)

Answer 7

Maybe

Answer 8

a = 6x and b = 15x .

Answer 9

yes but what I dont get is what happens with the x

Answer 10

Not sure

Answer 11

\[\sqrt{6x*15x}=\sqrt{9*10*x^2}\]
right ?

Answer 12

\[x ^{2}?

Answer 13

Don't no

Answer 14

how did you get 9 and 10

Answer 15

Welcome to Openstudy(Op) @killer-DonzZ

Answer 16

Added it

Answer 17

Ok

Answer 18

15*6=(3*5)*(2*3)=\(3^2\)*5*2=9*10 got it ?

Answer 19

ok got it but x becomes x^2?

Answer 20

Thank you tennistar

Answer 21

no..
\[\sqrt{a}=a^{\frac{1}{2}}\]
\[\sqrt{x^2}=x^2{\frac{1}{2}}=x^{2*\frac{1}{2}}=x^1=x\]

Answer 22

remember also that :\([a^m]^n=a^{mn}\)

Answer 23

so my whole questions is \[3\sqrt{6x}*2\sqrt{15x}\]
is \[18x \sqrt{10}\]

Answer 24

right?

Answer 25

gr8 very right

Answer 26

thanks

Answer 27

ur welcome