Mathematics
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OpenStudy (anonymous):
find the domain and range. g(x)=2/x-1.
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OpenStudy (anonymous):
Would the domain be all real numbers, but x cannot equal 1
OpenStudy (ash2326):
yeah, correct
OpenStudy (anonymous):
I just ned help with range
OpenStudy (ash2326):
okay, let me think
just a moment
OpenStudy (anonymous):
ok:)
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OpenStudy (anonymous):
May I help??
OpenStudy (ash2326):
feel free to join in always @waterineyes
OpenStudy (anonymous):
For finding range we have to find x in terms of g(x)..
OpenStudy (anonymous):
hmm
OpenStudy (ash2326):
oops I made a mistake
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OpenStudy (anonymous):
Put g(x) = y for simplicity:
\[(x-1)y = 2 \implies xy - y = 2 \implies xy = 2+y \implies x = \frac{2+y}{y}\]
Now you know what y cannot take..
OpenStudy (anonymous):
Have you got or not??
OpenStudy (anonymous):
y cannot be 2?
OpenStudy (anonymous):
No dear check for denominator..
OpenStudy (anonymous):
Im not sure,,
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OpenStudy (anonymous):
It is just like as you have found Domain..
y cannot be 0.
Right or not??
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so my range is just y can't be o
OpenStudy (anonymous):
0
OpenStudy (ash2326):
@waterineyes good work
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OpenStudy (anonymous):
Yes all real except 0..
OpenStudy (anonymous):
thanks so much . I'm posting another one now so if you don't mind, plz look! thanks!
OpenStudy (anonymous):
Remember:
For Domain, we find x..
For range, we find y or f(x)..
OpenStudy (anonymous):
@ash2326 just learning it from you..