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Given the following triangle, solve for angle Y. 49.54° 51.89° 54.23° 57.12°
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sin(90)/4.6 = sin(y)/3.5
\(\arcsin {3.5 \over 4.6} = Y\)
y = sin^-1((3.5)sin(90)/4.6)
Hmm. You just need to input \(\sin ^{-1} {3.5 \over 4.6}\) into a calculator.
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and dance!
c?
\(\sin^{-1}\) retricein arcsin, not 1/sin.
Depends on your calculator. We are lazy to calculate :/
a
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thanks :)
A)
Wolfram cheater >:(
did you do it in your head?
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what is the dif in wolfram or a calculator?
No I used a trig table :-)
cheater
pft
exactly m8
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:P
you really used a chart? why?
Lazyness ftw (No because I have my textbook :D)
ahhh, i was trying to use log charts the other day. dear lord we are lucky
xD
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