Help please! my username is mathdummy for a reason!...Find constants A and B that make the equation true 2x-9/x^2- x- 6 = A/x-3 + B/x+2
lol smoothmath you probably think im a true math idiot by now
First off i would like you to factor the denominator of the left hand side
^What he said
can't i multiply to set the denominators equal first?
i see nothing suspicious in asking questions from substitution to calculus and then to partial fractions..
if you can see it go ahead but i think that might be complicating the scenario
lol @lgbasallote
look igbasallote idk what to tell ya..if you don't believe me or dont want to believe me fine..but trust me when i say im not getting on here and asking math questions for fun...im taking several online courses and this just happens to be whats thrown at me
Interesting.
after you factor, and then multiply the denominator, you should have something like this 2x - 9 = A(x+2) + B(x-3)
Do you understand how i got to that step
ya that makes sense to me...
now, the next step will be to distribute the A and the B Show me what you get when you finish
2x-9 = Ax + 2A + Bx - 3B.... 2x = Ax + Bx -9 = 2A - 3B 2 = A + B -9 = 2A - 3B 6 = 3A + 3B -9 = 2A - 3B +.....am i doing this right so far??
Looks right
yes
At this point, 2 = A + B -9 = 2A - 3B we can do substitution. 2 = A + B, can be written as ; A = 2 - B
then substitute A into the other equation ( -9 = 2A - 3B )
try it it should be easy from here. First you will get B. And then you can solve for A
Okay so for my final answer i got B = 13/5 and A = 3/5...look right?
yes
thanks so much for your help!!
Anytime
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